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Cartesian Plane/Coordinates Simplified Revision Notes

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Cartesian Plane/Coordinates

What is the Cartesian Plane?

The Cartesian plane is a two-dimensional plane used for plotting points, lines, and shapes. It is defined by two perpendicular axes:

  • xaxisx-axis (horizontal)
  • yaxisy-axis (vertical) These axes intersect at the origin, denoted as (0,0)(0, 0).

The plane is divided into four quadrants:

  1. Quadrant I: Both xx and yy are positive.
  2. Quadrant II: xx is negative, yy is positive.
  3. Quadrant III: Both xx and yy are negative.
  4. Quadrant IV: xx is positive, yy is negative.

Coordinates of a Point

A point on the Cartesian plane is represented by an ordered pair (x,yx, y):

  • xx: The horizontal distance from the origin.
  • yy: The vertical distance from the origin. For example, the point (3,2)(3, -2) is located 3 units to the right of the origin and 2 units down.

Distance Formula

The distance dd between two points (x1,y1x_1, y_1) and (x2,y2x_2, y_2) is given by:

d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Midpoint Formula

The midpoint MM of the line segment joining two points (x1,y1x_1, y_1) and (x2,y2x_2, y_2) is:

M=(x1+x22,y1+y22)M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)

Equation of a Line

A straight line on the Cartesian plane can be represented by its equation in the form:

y=mx+cy = mx + c

where:

  • mm is the slope of the line, calculated as y2y1x2x1\frac{y_2 - y_1}{x_2 - x_1}
  • cc is the yintercepty-intercept, the point where the line crosses the yaxisy-axis.

Worked Examples

infoNote

Example 1: Find the Distance Between Two Points

Problem: Find the distance between A(1,2)A(1, 2) and B(4,6)B(4, 6).


Solution:

Using the distance formula:

d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Substitute (x1,y1)=(1,2)(x_1, y_1) = (1, 2) and (x2,y2)=(4,6)(x_2, y_2) = (4, 6):

d=(41)2+(62)2=32+42d = \sqrt{(4 - 1)^2 + (6 - 2)^2} = \sqrt{3^2 + 4^2} =9+16=25=5= \sqrt{9 + 16} = \sqrt{25} = 5

Answer: The distance is 55 units.

infoNote

Example 2: Find the Midpoint of a Line Segment

Problem: Find the midpoint of the segment joining A(3,4)A(-3, 4) and B(5,2)B(5, -2).


Solution:

Using the midpoint formula:

M=(x1+x22,y1+y22)M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)

Substitute (x1,y1)=(3,4)(x_1, y_1) = (-3, 4) and (x2,y2)=(5,2)(x_2, y_2) = (5, -2)

M=(3+52,4+(2)2)=(22,22)=(1,1)M = \left( \frac{-3 + 5}{2}, \frac{4 + (-2)}{2} \right) = \left( \frac{2}{2}, \frac{2}{2} \right) = (1, 1)

Answer: The midpoint is (1,1)(1, 1)


Summary

  • The Cartesian plane is defined by two perpendicular axes (xx and yy) intersecting at the origin (0,0)(0, 0)
  • Points are represented by ordered pairs (x,y)(x, y)
  • Key formulas:
    • Distance formula: d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
    • Midpoint formula: M=(x1+x22,y1+y22)M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
    • Line equation: y=mx+cy = mx + c, where m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}
  • Practice applying these concepts to strengthen understanding.
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