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Differentiating Expressions Simplified Revision Notes

Revision notes with simplified explanations to understand Differentiating Expressions quickly and effectively.

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Differentiating Expressions

Introduction

Differentiation is a fundamental concept in calculus that deals with the rate at which a function changes. It is the process of finding the derivative of a function, which represents the slope of the function's graph at any given point.

If f(x)f(x) is a function, the f(x)f'(x) is the derivative of that expression.

The following animation represents the different points of the first derivative of the function f(x)=xsin(x2)+1f(x)=x \sin(x^2)+1. At steep regions, the slope is also steep, and at shallow or flat regions, the slope is also shallow or flat.


image

Differentiating by Terms

The simplest form of differentiation is differentiating term by term. Informally, we multiply the power of that term with the coefficient and subtract 11 from the power. In general :

f(x)=axn    f(x)=anxn1f(x)=ax^n \implies f'(x)=anx^{n-1}

Example

infoNote

Differentiate f(x)=2x3f(x)=-2x^3

2(3)x31=6x2-2(3)x^{3-1}=-6x^2

Example

infoNote

Differentiate f(x)=7xf(x)=7x

7(1)x11=7x0=7(1)=77(1)x^{1-1}=7x^0=7(1)=7

Example

infoNote

Differentiate f(x)=x3+2x2+3x+8f(x)=-x^3+2x^2+3x+8

For polynomial expressions with multiple terms, differentiate each term separately.

f(x)=3x2+4x+3f'(x)=-3x^2+4x+3
infoNote

The derivative of a constant is 00. Why ?, If :

f(x)=3f(x)=3

Then you can rewrite the expression as :

f(x)=3x0f(x)=3x^0

Differentiate :

f(x)=3(0)x01=0f'(x)=3(0)x^{0-1}=0

Example

infoNote

Differentiate f(x)=1xf(x)=\frac{1}{x}

When possible, try to rewrite the expression in index form. We can use indices rules :

f(x)=1x=x1f(x)=\frac{1}{x}=x^{-1}f(x)=(1)x11=x2f'(x)=(-1)x^{-1-1}=-x^{-2}

While not wrong, it's typically bad practice to have negative powers. Convert back to index form.

x2=1x2-x^{-2}=-\frac{1}{x^2}

Example

infoNote

Differentiate f(x)=2xf(x)=2\sqrt{x}

f(x)=2x=2x12f(x)=2\sqrt{x}=2x^{\frac{1}{2}}f(x)=(12)2x121=x12=1xf'(x)=\left(\tfrac{1}{2} \right)2x^{\frac{1}{2}-1}=x^{-\frac{1}{2}}=\frac{1}{\sqrt{x}}
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