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Products to Sums and Differences Simplified Revision Notes

Revision notes with simplified explanations to understand Products to Sums and Differences quickly and effectively.

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Products to Sums and Differences

What Are Products to Sums and Differences?

The "products to sums and differences" formulas are trigonometric identities that transform the product of sine and cosine functions into a sum or difference. These formulas simplify complex expressions and make solving equations more manageable.

The Formulas:

  1. sinAcosB=12[sin(A+B)+sin(AB)]\sin A \cos B = \frac{1}{2}[\sin(A + B) + \sin(A - B)]
  2. cosAsinB=12[sin(A+B)sin(AB)]\cos A \sin B = \frac{1}{2}[\sin(A + B) - \sin(A - B)]
  3. cosAcosB=12[cos(A+B)+cos(AB)]\cos A \cos B = \frac{1}{2}[\cos(A + B) + \cos(A - B)]
  4. sinAsinB=12[cos(A+B)cos(AB)]\sin A \sin B = -\frac{1}{2}[\cos(A + B) - \cos(A - B)] These formulas are essential for integration, signal processing, and simplifying expressions involving trigonometric functions.

How Are These Formulas Derived?

The products-to-sums formulas come from the addition and subtraction identities for sine and cosine:

  • sin(A±B)=sinAcosB±cosAsinB\sin(A \pm B) = \sin A \cos B \pm \cos A \sin B
  • cos(A±B)=cosAcosBsinAsinB\cos(A \pm B) = \cos A \cos B \mp \sin A \sin B
infoNote

Example : Derivation sinAcosB\sin A \cos B

Using the sum and difference identities:

sin(A+B)=sinAcosB+cosAsinB\sin(A + B) = \sin A \cos B + \cos A \sin Bsin(AB)=sinAcosBcosAsinB\sin(A - B) = \sin A \cos B - \cos A \sin B

Adding these equations:

sin(A+B)+sin(AB)=2sinAcosB\sin(A + B) + \sin(A - B) = 2\sin A \cos B

Dividing both sides by 2:

sinAcosB=12[sin(A+B)+sin(AB)]\sin A \cos B = \frac{1}{2}[\sin(A + B) + \sin(A - B)]

Why Use These Formulas?

The products-to-sums identities help:

  • Simplify trigonometric expressions.
  • Solve trigonometric equations.
  • Evaluate integrals involving trigonometric products.

Worked Examples

infoNote

Example 1:

Simplify sin3xcos2x\sin 3x \cos 2x.

Using the formula:

sinAcosB=12[sin(A+B)+sin(AB)]\sin A \cos B = \frac{1}{2}[\sin(A + B) + \sin(A - B)]

Substitute A=3xA = 3x and B=2xB = 2x:

sin3xcos2x=12[sin(3x+2x)+sin(3x2x)]\sin 3x \cos 2x = \frac{1}{2}[\sin(3x + 2x) + \sin(3x - 2x)]=12[sin5x+sinx]= \frac{1}{2}[\sin 5x + \sin x]
infoNote

Example 2:

Simplify cos4xcos2x\cos 4x \cos 2x

Using the formula:

cosAcosB=12[cos(A+B)+cos(AB)]\cos A \cos B = \frac{1}{2}[\cos(A + B) + \cos(A - B)]

Substitute A=4xA = 4x and B=2xB = 2x:

cos4xcos2x=12[cos(4x+2x)+cos(4x2x)]\cos 4x \cos 2x = \frac{1}{2}[\cos(4x + 2x) + \cos(4x - 2x)]=12[cos6x+cos2x]= \frac{1}{2}[\cos 6x + \cos 2x]

Summary:

  • The products to sums and differences formulas convert products of sine and cosine functions into sums or differences.
  • These are helpful for simplifying expressions and solving equations.
  • Key formulas to remember:
sinAcosB=12[sin(A+B)+sin(AB)]\sin A \cos B = \frac{1}{2}[\sin(A + B) + \sin(A - B)] cosAsinB=12[sin(A+B)sin(AB)]\cos A \sin B = \frac{1}{2}[\sin(A + B) - \sin(A - B)] cosAcosB=12[cos(A+B)+cos(AB)]\cos A \cos B = \frac{1}{2}[\cos(A + B) + \cos(A - B)] sinAsinB=12[cos(A+B)cos(AB)]\sin A \sin B = -\frac{1}{2}[\cos(A + B) - \cos(A - B)]
  • Practice applying these formulas in different scenarios for mastery.
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