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Sample Answer for To show that acceleration is directly proportional to the force applied

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To show that a ∝ F

Apparatus

Air-track with one vehicle, pulley and blower, two photogates, two retort stands, dual timer, metre-stick, black card, set of slotted weights (1 N total).

Experimental Setup

Procedure

  • Set up the apparatus as in the diagram. Make sure the card cuts both light beams as it passes along the track.

  • Allow the trolley to roll down the runway.

  • Level the air track.

  • Set the weights F at 1 N. With the card at one end of the track start the blower and release the card from rest.

  • Note the times t₁ and t₂.

  • Remove one 0.1 N disc from the slotted weight, store this on the vehicle, and repeat.

  • Continue for values of F from 1.0 N to 0.1 N.

  • Use a metre-stick to measure the length of the card l and the separation of the photogate beams s.

  • Record results as shown.

  • Draw a graph of a/m s⁻² against F/N.


To show that a ∝ F

Diagram

Results

ll = .......... mm.

ss = .......... mm.

Initial velocity u=lt1u = \frac{l}{t_1}

Final velocity v=lt2v = \frac{l}{t_2}

Acceleration a=v2u22sa = \frac{v^2 - u^2}{2s}

F/Nt1t_1/Nt2t_2/Nu/m s1^{-1}v/m s1^{-1}a/m s2^{-2}
1.0
0.9
0.8
0.7
0.6
0.5
0.4
0.3
0.2
0.1

Conclusion

A straight line through the origin shows that, for a constant mass, the acceleration is proportional to the applied force.

infoNote

Note

Ignore the initial five or six dots on the tape since the trolley may not be moving with constant acceleration during this time interval.

Ticker timers that use precarbonated tape are recommended because the friction due to paper drag is reduced.

Ensure that the voltage rating of the timer is not exceeded.

Some timers make one hundred dots in one second.

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