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10 questions from this quiz
Parabola
y2=kxy^2 = kxy2=kx
(±a,0)(\pm a, 0)(±a,0) and (0,±b)(0, \pm b)(0,±b)
When a=ba = ba=b
yyy-axis
y=±baxy = \pm \frac{b}{a}xy=±abx
x=0x = 0x=0 and y=0y = 0y=0
(−2,3)(-2, 3)(−2,3)
(5,−2)(5, -2)(5,−2)
Swap xxx and yyy in equation
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