Equation of a Trajectory (AQA A-Level Mathematics): Flashcards

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Equation of a Trajectory
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What is the equation of trajectory?

Describes the path of a projectile in parabolic form

Shape of projectile trajectory

Parabola

Assumptions for trajectory equation

Constant gravity acceleration & no air resistance

Horizontal displacement formula (projectile)

x=ucos⁡(θ)⋅tx = u \cos(\theta) \cdot t

Vertical displacement formula (projectile)

y=usin⁡(θ)⋅t−12gt2y = u \sin(\theta) \cdot t - \frac{1}{2} g t^2

Trajectory equation in xx and yy

y=xtan⁡(θ)−gx22u2cos⁡2(θ)y = x \tan(\theta) - \frac{g x^2}{2u^2 \cos^2(\theta)}

Initial velocity form for horizontal projectile

(u,0)ms−1(u, 0) ms^{-1} where uu is horizontal speed

Force on horizontal projectile after launch

Weight only

Method to get Cartesian equation from parametric

Eliminate time tt

SUVAT equation for displacement with time

s=ut+12at2\mathbf{s} = \mathbf{ut} + \frac{1}{2} \mathbf{a}t^2

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