Normal Approximation of Binomial (AQA A-Level Mathematics): Flashcards

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Normal Approximation of Binomial
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Conditions for Normal approx. to Binomial

Large nn, np≥5np \geq 5, n(1−p)≥5n(1-p) \geq 5

First probability condition for Normal approx. to Binomial

np≥5np \geq 5

Second probability condition for Normal approx. to Binomial

n(1−p)≥5n(1-p) \geq 5

Mean (μ\mu) for Normal approx. to Binomial

npnp

Standard deviation (σ\sigma) for Normal approx. to Binomial

np(1−p)\sqrt{np(1-p)}

What is continuity correction?

Adjusting bounds when converting discrete to continuous dist.

Amount to adjust in continuity correction

0.50.5

Why continuity correction is needed

Normal is continuous, Binomial is discrete

Formula to convert to zz-scores in Normal approx.

Z=X−μσZ = \frac{X - \mu}{\sigma}

Why np≥5np \geq 5 and n(1−p)≥5n(1-p) \geq 5 conditions?

Ensures Binomial is bell-shaped for Normal approx.

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