Parametric Equations - Eliminating the Parameter (AQA A-Level Mathematics): Quizzes

To find a direct relationship between $x$ and $y$

A Cartesian equation in $x$ and $y$

The simpler of the two equations

$t = \frac{x - 3}{2}$

$y = \frac{(x - 3)^2}{4} - 1$

$\sin^2 t + \cos^2 t = 1$

Square both equations, then add

$x^2 + y^2 = 1$

A circle with centre (0,0) and radius 1

$\left(\frac{x-1}{5}\right)^2+\frac{y^2}{36}=1$