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10 questions from this quiz
sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1sin2θ+cos2θ=1
1+tan2θ=sec2θ1 + \tan^2 \theta = \sec^2 \theta1+tan2θ=sec2θ
1cosθ\frac{1}{\cos \theta}cosθ1
sinθcosθ\frac{\sin \theta}{\cos \theta}cosθsinθ
cosθ\cos \thetacosθ
cos(−θ)=cosθ\cos(-\theta) = \cos \thetacos(−θ)=cosθ
2sinθcosθ2 \sin \theta \cos \theta2sinθcosθ
Identical to (true for all values)
−32-\frac{\sqrt{3}}{2}−23
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