Ideal gases (AQA A-Level Physics): Revision Notes
Ideal gases
Gas laws
The gas laws show how pressure (p), volume (V), and temperature (T) are related for a fixed mass of gas. These laws are based on experimental observations rather than theoretical predictions. There are three gas laws you need to understand:
The gas laws are empirical - they were discovered through careful experimental measurements, not derived from theory. This makes them particularly powerful for practical applications.
Boyle's law
When temperature is held constant, pressure and volume are inversely proportional. This means that as one increases, the other decreases proportionally.
The equation for Boyle's law is:
where is a constant value for that particular gas sample at that temperature.
Worked Example: Applying Boyle's Law
A gas occupies a volume of 2.0 m³ at a pressure of 100 kPa. If the pressure increases to 250 kPa at constant temperature, what is the new volume?
Solution:
Using Boyle's law:
Step 1: Identify known values
- kPa
- m³
- kPa
Step 2: Rearrange and solve
The volume decreases to 0.8 m³ as pressure increases.
Charles' law
When pressure is held constant, volume is directly proportional to absolute temperature. This means that as temperature increases, volume increases proportionally.
The equation for Charles' law is:
where is a constant value for that particular gas sample at that pressure.
Charles' law only works when temperature is measured in kelvin (K), not Celsius. Always convert temperature to kelvin before applying this law!
The pressure law
When volume is held constant, pressure is directly proportional to absolute temperature. This means that as temperature increases, pressure increases proportionally.
The equation for the pressure law is:
where is a constant value for that particular gas sample at that volume.
Absolute temperature and the kelvin scale
All thermal physics equations require temperature to be measured in kelvin (K), which is the absolute scale of temperature. The relationship between temperature changes is straightforward: a change of 1 K equals a change of 1°C.
To convert between Celsius and kelvin, use:
where is the temperature in kelvin and is the temperature in Celsius.
The kelvin scale is an absolute temperature scale because it starts from absolute zero. Unlike Celsius or Fahrenheit, kelvin has no negative values - it begins at the lowest possible temperature in the universe.
Absolute zero
Absolute zero is the lowest temperature possible in the universe. It occurs at -273°C, which equals 0 K on the kelvin scale. At absolute zero, particles possess no kinetic energy whatsoever, and both the volume and pressure of a gas theoretically reach zero.
Absolute zero represents a fundamental limit in physics. At this temperature:
- All molecular motion ceases (classically)
- Gases would have zero volume and zero pressure
- No heat energy can be extracted from a substance
- It is impossible to reach in practice, though scientists have come very close
The ideal gas equation
The three gas laws can be combined into a single relationship. When you consider all three laws together, you get:
However, the constant depends on the amount of gas present, which is measured in moles (). This leads to a more useful form:
where is the number of moles of gas, and is the molar gas constant.
The molar gas constant has the value:
Rearranging this relationship gives the ideal gas equation:
This equation allows you to calculate any one variable (pressure, volume, number of moles, or temperature) if you know the other three.
Units Matter!
When using the ideal gas equation, ensure your units are consistent:
- Pressure () in pascals (Pa)
- Volume () in cubic meters (m³)
- Temperature () in kelvin (K)
- Number of moles () in mol
- Gas constant () = 8.31 J mol⁻¹ K⁻¹
Worked Example: Using the Ideal Gas Equation
Calculate the pressure of 0.50 moles of gas at 300 K occupying a volume of 0.012 m³.
Solution:
Using
Step 1: Identify known values
- mol
- J mol⁻¹ K⁻¹
- K
- m³
Step 2: Rearrange for pressure
Step 3: Substitute and calculate
The pressure is 104 kPa (to 3 significant figures).
Moles and molecules
One mole of any substance contains exactly atoms or molecules. This number is called the Avogadro constant ():
You can convert between the number of moles () and the number of molecules () using:
or rearranged:
The Avogadro constant provides the bridge between the microscopic world (individual molecules) and the macroscopic world (measurable quantities in moles). This is fundamental to chemistry and physics calculations.
Alternative form of the ideal gas equation
By substituting the relationship between molecules and moles into the ideal gas equation, you can express it in terms of the number of molecules rather than moles:
This can be simplified further using the Boltzmann constant (), which is defined as:
This leads to the alternative form:
This form is particularly useful when working with individual molecules rather than bulk quantities measured in moles.
The Boltzmann constant ( J K⁻¹) connects the microscopic properties of individual particles to macroscopic thermodynamic properties. Use this form when dealing with molecular-level calculations.
Molar mass
Molar mass is the mass (in grams) of one mole of a substance. You can determine the molar mass by finding the relative molecular mass, which equals approximately the sum of all nucleons (protons and neutrons) in one molecule of the substance.
Worked Example: Calculating Molar Mass
Calculate the molar mass of carbon dioxide (CO₂).
Solution:
Step 1: Identify the atoms in one molecule
- 1 carbon atom (C)
- 2 oxygen atoms (O)
Step 2: Find the nucleon numbers
- Carbon: approximately 12 nucleons
- Oxygen: approximately 16 nucleons each
Step 3: Calculate total molar mass Molar mass = 12 + (2 × 16) = 12 + 32 = 44 g mol⁻¹
Therefore, oxygen gas (O₂) has two oxygen atoms, each with approximately 16 nucleons, giving a molar mass of approximately 32 g mol⁻¹.
Work done by gases
When a gas changes volume at constant pressure, work is done. This typically occurs through the transfer of thermal energy to or from the gas. The work done can be calculated using:
where is the pressure and is the change in volume.
Pressure-Volume Graphs
On a pressure-volume (p-V) graph, the work done by or on the gas equals the area under the curve. This geometric interpretation is extremely useful for analyzing complex thermodynamic processes.
When analyzing these graphs:
- Gas expands (positive ) → gas does work on its surroundings
- Gas is compressed (negative ) → work is done on the gas
Worked Example: Work Done by Gas Expansion
A gas expands at a constant pressure of 200 kPa. Its volume increases from 0.003 m³ to 0.007 m³. Calculate the work done by the gas.
Solution:
Using
Step 1: Calculate the change in volume
Step 2: Convert pressure to Pa
Step 3: Calculate work done
The gas does 800 J of work on its surroundings.
Key Points to Remember:
-
The ideal gas equation combines all three gas laws, where J mol⁻¹ K⁻¹
-
Always convert temperature to kelvin using before using any gas law equations
-
Absolute zero (0 K or -273°C) is the lowest possible temperature where particles have no kinetic energy
-
The Avogadro constant ( mol⁻¹) allows conversion between moles and molecules, leading to the alternative form
-
Work done by a gas at constant pressure is calculated using , which equals the area under a pressure-volume graph
-
When using gas equations, ensure consistent units: pressure in Pa, volume in m³, temperature in K