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10 questions from this quiz
It remains unchanged
v⊥,after=−ev⊥,beforev_{\perp, \text{after}} = -e v_{\perp, \text{before}}v⊥,after=−ev⊥,before
0≤e≤10 \leq e \leq 10≤e≤1
hn=e2nh0h_n = e^{2n} h_0hn=e2nh0
v⊥,n=(−e)nv⊥,0v_{\perp, n} = (-e)^n v_{\perp, 0}v⊥,n=(−e)nv⊥,0
4 ms−14 \, \text{ms}^{-1}4ms−1
0.64 m0.64 \, \text{m}0.64m
(50)\begin{pmatrix} 5 \\ 0 \end{pmatrix}(50)
Some kinetic energy is lost
v=2ghv = \sqrt{2gh}v=2gh
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