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10 questions from this quiz
Position vector of any point on the line
Position vector of a fixed point
Direction vector of the line
A scalar parameter
They are equivalent
r=(2,−1,3)+λ(1,0,2)\mathbf{r} = (2, -1, 3) + \lambda(1, 0, 2)r=(2,−1,3)+λ(1,0,2)
x−12=y−2−1=z−34\frac{x-1}{2} = \frac{y-2}{-1} = \frac{z-3}{4}2x−1=−1y−2=4z−3
By eliminating λ\lambdaλ
(3,−2,5)(3, -2, 5)(3,−2,5)
Confusing position and direction vectors
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