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10 questions from this quiz
dydx=f(x,y)\frac{dy}{dx} = f(x, y)dxdy=f(x,y)
Simplifies equations
Back-substitute original variables
r′sinθ+rcosθ=0r' \sin \theta + r \cos \theta = 0r′sinθ+rcosθ=0
r′cosθ−rsinθ=0r' \cos \theta - r \sin \theta = 0r′cosθ−rsinθ=0
F(x)=e∫P(x) dxF(x) = e^{\int P(x) \, dx}F(x)=e∫P(x)dx
1+dydx1 + \frac{dy}{dx}1+dxdy
−sinθ-\sin \theta−sinθ
3x\frac{3}{x}x3
Neglecting to back-substitute
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