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10 cards from this deck
It shows possible outcomes and their probabilities.
There are 18 discs in total: 5 red, 6 blue, 7 green.
P(RR)=(5/18)×(4/17)=20/306=10/153P(RR) = (5/18) \times (4/17) = 20/306 = 10/153P(RR)=(5/18)×(4/17)=20/306=10/153.
Sum probabilities of outcomes with at least one green.
Use 1−P(no green discs)1 - P(\text{no green discs})1−P(no green discs) for calculation.
P(G∣B)=7/17P(G|B) = 7/17P(G∣B)=7/17 after first disc selection.
Use P(R,B)/P(B)P(R,B)/P(B)P(R,B)/P(B) conditional probability formula.
P(RB)=551P(RB) = \frac{5}{51}P(RB)=515 from previous outcomes.
P(B)=17/51P(B) = 17/51P(B)=17/51 from all outcomes with blue second.
P(R∣B)=P(R and B)/P(B)P(R|B) = P(R \text{ and } B) / P(B)P(R∣B)=P(R and B)/P(B) for calculating.
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