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10 questions from this quiz
At its centre
0.750.750.75 m
5gsin30∘×0.75−Fcos30∘×1.5=05g \sin30^\circ \times 0.75 - F \cos30^\circ \times 1.5 = 05gsin30∘×0.75−Fcos30∘×1.5=0
F=5gsin30∘×0.75cos30∘×1.5F=\frac{5g \sin 30^\circ \times 0.75}{\cos 30^\circ \times 1.5}F=cos30∘×1.55gsin30∘×0.75
14.1514.1514.15 N
0.75sin30°0.75 \sin 30°0.75sin30°
1.5cos30°1.5 \cos 30°1.5cos30°
Hinge reaction forces
Sum of moments =0= 0=0
Midpoint of rod
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