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10 questions from this quiz
vu′−uv′v2\frac{vu' - uv'}{v^2}v2vu′−uv′
The denominator
[v(x)]2[v(x)]^2[v(x)]2
Identify u(x)u(x)u(x) and v(x)v(x)v(x)
−4x(x2−1)2\frac{-4x}{(x^2 - 1)^2}(x2−1)2−4x
xcos(x)−sin(x)x2\frac{x\cos(x) - \sin(x)}{x^2}x2xcos(x)−sin(x)
exe^xex
3e3x3e^{3x}3e3x
−8c(4x−c)2\frac{-8c}{(4x-c)^2}(4x−c)2−8c
dydx=−8c(4x−c)2\frac{dy}{dx} = \frac{-8c}{(4x-c)^2}dxdy=(4x−c)2−8c never equals 0
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