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10 questions from this quiz
Variable in the index power
Initial value at t=0t = 0t=0
k>0k > 0k>0
Increases as the quantity grows
y=y0e−kty = y_0 e^{-kt}y=y0e−kt
Radioactive decay & depreciation
ln(2)k\frac{\ln(2)}{k}kln(2)
yyy is multiplied by 2
Take natural logarithm
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