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10 questions from this quiz
2sinθcosθ2\sin \theta \cos \theta2sinθcosθ
12[cos(A−B)−cos(A+B)]\frac{1}{2}[\cos(A - B) - \cos(A + B)]21[cos(A−B)−cos(A+B)]
Let u=sinθu = \sin \thetau=sinθ or cosθ\cos \thetacosθ
Trigonometric functions are periodic
θ=θ0+180∘n\theta = \theta_0 + 180^\circ nθ=θ0+180∘n
θ=θ0+360∘n\theta = \theta_0 + 360^\circ nθ=θ0+360∘n
To check for extraneous solutions
a2+b2\sqrt{a^2 + b^2}a2+b2
ba\frac{b}{a}ab
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