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10 questions from this quiz
BC→=AD→\overrightarrow{BC} = \overrightarrow{AD}BC=AD
(60)\begin{pmatrix} 6 \\ 0 \end{pmatrix}(60)
(4−1)\begin{pmatrix} 4 \\ -1 \end{pmatrix}(4−1)
(42)\begin{pmatrix} 4 \\ 2 \end{pmatrix}(42) & (−1−12)\begin{pmatrix} -1 \\ -\frac{1}{2} \end{pmatrix}(−1−21)
Two pairs of parallel sides
Four sides of the same length
AB→=CD→\overrightarrow{AB} = \overrightarrow{CD}AB=CD and BC→=AD→\overrightarrow{BC} = \overrightarrow{AD}BC=AD
False, as 1×−14≠−11 \times -\frac{1}{4} \neq -11×−41=−1
(0,−1)(0, -1)(0,−1)
Two pairs of parallel sides and right angles
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