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Maths Skill: Calculating Maximum Impulse Frequency Simplified Revision Notes

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6.2.6 Maths Skill: Calculating Maximum Impulse Frequency

infoNote

To calculate the maximum frequency at which action potentials can be transmitted along a neurone, you need to consider the refractory period.

Key Concepts

  • Refractory period:
    • The time during which a neurone cannot fire another action potential.
    • It includes the absolute refractory period (no impulse possible) and relative refractory period (requires a stronger stimulus to generate an impulse).
  • Impulse frequency:
    • The number of action potentials transmitted per second.

Formula for Maximum Frequency:

Maximum impulse frequency (Hz)=1Refractory period (s)\text{Maximum impulse frequency (Hz)} = \frac{1}{\text{Refractory period (s)}}
  • Units:
    • Refractory period must be in seconds (s) for the calculation to give frequency in Hertz (Hz).
    • 1 Hz = 1 action potential per second.

Worked Example

If the refractory period is 2 ms (milliseconds):

  1. Convert milliseconds to seconds:
  • 2 ms = 2 × 10^{-3} s
  1. Apply the formula: Answer: The maximum frequency is 500 Hz.
Maximum impulse frequency=12×103=500Hz\text{Maximum impulse frequency} = \frac{1}{2 \times 10^{-3}} = 500 \, \text{Hz}
infoNote

Exam Tips:

  • Ensure you convert the refractory period into seconds before calculating.
  • Understand that the shorter the refractory period, the higher the maximum frequency of impulses.
  • Be prepared to explain how the refractory period ensures discrete signals and limits the frequency of impulses.
infoNote

Summary:

  • Use .
Maximum Frequency=1Refractory Period (s)\text{Maximum Frequency} = \frac{1}{\text{Refractory Period (s)}}
  • Always convert milliseconds to seconds before substituting.
  • Be able to relate this to the physiological role of the refractory period in neurones.
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