Maths Skill: Calculating Maximum Impulse Frequency Simplified Revision Notes for A-Level AQA Biology
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6.2.6 Maths Skill: Calculating Maximum Impulse Frequency
infoNote
To calculate the maximum frequency at which action potentials can be transmitted along a neurone, you need to consider the refractory period.
Key Concepts
Refractory period:
The time during which a neurone cannot fire another action potential.
It includes the absolute refractory period (no impulse possible) and relative refractory period (requires a stronger stimulus to generate an impulse).
Impulse frequency:
The number of action potentials transmitted per second.
Formula for Maximum Frequency:
Maximum impulse frequency (Hz)=Refractory period (s)1
Units:
Refractory period must be in seconds (s) for the calculation to give frequency in Hertz (Hz).
1 Hz = 1 action potential per second.
Worked Example
If the refractory period is 2 ms (milliseconds):
Convert milliseconds to seconds:
2 ms = 2 × 10^{-3} s
Apply the formula:
Answer: The maximum frequency is 500 Hz.
Maximum impulse frequency=2×10−31=500Hz
infoNote
Exam Tips:
Ensure you convert the refractory period into seconds before calculating.
Understand that the shorter the refractory period, the higher the maximum frequency of impulses.
Be prepared to explain how the refractory period ensures discrete signals and limits the frequency of impulses.
infoNote
Summary:
Use .
Maximum Frequency=Refractory Period (s)1
Always convert milliseconds to seconds before substituting.
Be able to relate this to the physiological role of the refractory period in neurones.
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