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Circular motion Simplified Revision Notes

Revision notes with simplified explanations to understand Circular motion quickly and effectively.

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6.1.1 Circular motion

Circular Motion Basics

infoNote

When an object moves in a circular path at a constant speed, it is still accelerating because the velocity (which includes direction) is constantly changing. This type of acceleration, even without a change in speed, is known as centripetal acceleration. According to Newton's First Law of Motion, an object in motion will continue in a straight line unless acted upon by a resultant force. In circular motion, the resultant force that keeps the object moving in a curved path is the centripetal force, which acts towards the centre of the circle.

image
infoNote

Key Terms and Definitions:

  • Centripetal Force: The inward force that keeps an object moving in a circle.
  • Centripetal Acceleration: The acceleration directed towards the centre of the circular path.

Angular Speed (ω)

Angular speed (ωω) represents the angle an object moves through per unit time. It can be calculated using either:

ω=vrorω=2πT=2πf\omega = \frac{v}{r} \quad \text{or} \quad \omega = \frac{2\pi}{T} = 2\pi f

Where:

  • vv = linear speed,
  • rr = radius of the circular path,
  • TT = time period for one full revolution,
  • ff = frequency (number of revolutions per second).

Radians and Angular Measurements

Angles in circular motion are often measured in radians. One radian is the angle formed when the arc length is equal to the radius of the circle. The full circle is 2Ď€2\pi radians. Conversions:

  • Degrees to radians: multiply by Ď€180\frac{\pi}{180}
  • Radians to degrees: multiply by 180Ď€\frac{180}{\pi}
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Formulas for Circular Motion

  1. Centripetal Acceleration (aa):
a=v2r=ω2ra = \frac{v^2}{r} = \omega^2 r

This formula shows that acceleration depends on the speed and radius of the circular path.

  1. Centripetal Force (F): Using Newton's Second Law F=maF = ma the formula for centripetal force becomes:
F=mv2r=mω2rF = \frac{mv^2}{r} = m \omega^2 r

Where:

  • mm = mass of the object,
  • vv = speed of the object,
  • rr = radius of the circle,
  • ω\omega = angular speed.
infoNote

Example Problem

An object of mass 2 kg is moving at a speed of 5 m/s in a circular path of radius 3 m. Calculate the centripetal force acting on the object.

Solution: Using the centripetal force formula:

F=mv2rF = \frac{mv^2}{r}

Substitute values:

F=2×(5)23=2×253=503=16.67 NF = \frac{2 \times (5)^2}{3} = \frac{2 \times 25}{3} = \frac{50}{3} = 16.67 \, \text{N}

Thus, the centripetal force is 16.67 N.

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