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5.3.4 Strategy for Trigonometric Equations

Solving trigonometric equations can be challenging, but with a systematic approach, you can tackle them efficiently. Here's a general strategy to help you solve a wide range of trigonometric equations:

1. Understand the Equation

  • Identify which trigonometric function(s) are involved (e.g., sinθ,cosθ,tanθ\sin \theta, \cos \theta, \tan \theta).
  • Determine whether the equation is linear (e.g.,sinθ=12 \sin \theta = \frac{1}{2}), quadratic (e.g., 2sin2θsinθ1=02\sin^2 \theta - \sin \theta - 1 = 0), or involves multiple trigonometric functions.

2. Simplify the Equation

  • Isolate the trigonometric function: Get the trigonometric function (e.g.,sinθ,cosθ \sin \theta, \cos \theta) by itself on one side of the equation.
  • Factor or Simplify: If the equation is quadratic or more complex, try factoring, expanding, or simplifying using trigonometric identities.
  • Substitution: If multiple trigonometric functions are involved (e.g., sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1), consider substituting using identities to reduce the equation to one trigonometric function.

3. Use Trigonometric Identities

  • Apply identities such as the Pythagorean identities, double-angle identities, sum-to-product identities, or half-angle identities to simplify the equation.
  • Common identities include: sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1 tanθ=sinθcosθ\tan \theta = \frac{\sin \theta}{\cos \theta} sin(2θ)=2sinθcosθ\sin(2\theta) = 2\sin \theta \cos \theta

4. Solve the Simplified Equation

  • Linear Equations:
    • Solve for the angle by taking the inverse trigonometric function (e.g.,sin1,cos1,tan1 \sin^{-1}, \cos^{-1}, \tan^{-1}).
    • Consider all solutions within the given interval by accounting for the periodic nature of the trigonometric functions.
  • Quadratic Equations:
    • Factor if possible, or use the quadratic formula: u=b±b24ac2au = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
    • Back-substitute to solve for the angle.
    • Check for extraneous solutions, especially if you square both sides of the equation.

5. Consider the General Solution

  • Trigonometric functions are periodic, meaning they repeat their values at regular intervals.
  • For sinθ=kandcosθ=k:\sin \theta = k and \cos \theta = k:
    • θ=θ0+360n (or 2π\theta = \theta_0 + 360^\circ n\ (or\ 2\pi n) where n is any integer.
    • Include both primary solutions θ0and180θ0(or πθ0).\theta_0 and 180^\circ - \theta_0 (or\ \pi - \theta_0).
  • For tanθ=k:\tan \theta = k:
    • θ=θ0+180n(or πn).\theta = \theta_0 + 180^\circ n (or\ \pi n).

6. List All Solutions in the Given Interval

  • Ensure that all solutions are within the specified interval, typically 0to 3600^\circ to\ 360^\circ or 0 to 2π0\ to\ 2\pi radians.
  • Adjust the general solution accordingly to fit within this range.

7. Verify Solutions

  • Substitute each solution back into the original equation to ensure it satisfies the equation.
  • Discard any extraneous solutions that might have arisen from squaring both sides or other manipulations.
infoNote

Example Strategy Application:

Problem: Solve 2sin2θ3sinθ+1=0for0θ360.2\sin^2 \theta - 3\sin \theta + 1 = 0 for 0^\circ \leq \theta \leq 360^\circ.


  1. Identify: This is a quadratic trigonometric equation in sinθ.\sin \theta.
  2. Substitute: Let u =sinθ \sin \theta, so the equation becomes 2u23u+1=0.2u^2 - 3u + 1 = 0.
  3. Factor: Factor the quadratic: (2u1)(u1)=0(2u - 1)(u - 1) = 0 So, u = 12 or u=1.\frac{1}{2}\ or\ u = 1.
  4. Back-substitute: Replace uu with sinθ: \sin \theta:
  • sinθ=12\sin \theta = \frac{1}{2}
  • sinθ=1\sin \theta = 1
  1. Solve:
  • For sinθ=12:\sin \theta = \frac{1}{2}: θ=30,150\theta = 30^\circ, 150^\circ
  • For sinθ=1:\sin \theta = 1: θ=90\theta = 90^\circ
  1. List All Solutions: The solutions in the interval 0θ3600^\circ \leq \theta \leq 360^\circ are: θ=30,90,150\theta = 30^\circ, 90^\circ, 150^\circ
  2. Verify: Substitute these angles back into the original equation to ensure they are correct.

Summary:

  • Simplify the trigonometric equation using identities or substitution.
  • Solve the resulting equation for the variable.
  • Consider the periodic nature of trigonometric functions to find all solutions within the given interval.
  • Verify the solutions to ensure correctness.

Solving Trig Equations Involving Compound Angles

By "compound angle," we mean "an angle more complicated than just θ.\theta."

infoNote
  • Example: Solve sin(3θ)=0.42,0θ180\sin(3\theta) = 0.42, 0 \leq \theta \leq 180.
  • Notice we are solving for θ \theta, but the angle is 33 θ\theta within the sin\sin function.
  • 03θ540(×3)0 \leq 3\theta \leq 540 ( \times 3 )

  1. Modify the domain to find limits for the compound angle in the bracket.
  2. Find all solutions for our compound angle (in this case, it's 3θ3\theta)
  • 3θ=arcsin(0.42)24.853\theta = \arcsin(0.42) \approx 24.85^\circ
  • Calculator Steps:
  • Press [ sin1\sin^{-1} ] then the letters to recall this number.
  • Store long numbers by pressing [STO][ STO ] then a letter with a red letter.
  • Solutions: 3θ=:highlight[24.85,155.15,384.834,515.165]3\theta = :highlight[24.85^\circ, 155.15^\circ, 384.834^\circ, 515.165^\circ]
  1. Find θ\theta for each intermediate solution (in this case, divide all by 33):
  • θ=:success[8.278,51.72,128.3,171.7](4sf)\theta = :success[8.278^\circ, 51.72^\circ, 128.3^\circ, 171.7^\circ] (4sf)

infoNote

Example: Solve cos(x37.6)=0.17,0x540\cos(x - 37.6^\circ) = 0.17, 0 \leq x \leq 540.

  • x=:success[137.4,297.8,497.4](4sf)\boxed {x = :success[137.4^\circ, 297.8^\circ, 497.4^\circ] \quad \text{(4sf)}}

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