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f'(x)/f(x) Simplified Revision Notes

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8.2.4 f'(x)/f(x)

When you have an expression of the form  f(x)f(x)\ \frac{f'(x)}{f(x)} , where  f(x)\ f(x) is a differentiable function, you can recognize this as the derivative of the natural logarithm of  f(x)\ f(x) . This is because:

ddx[lnf(x)]=f(x)f(x)\\ \frac{d}{dx}[\ln|f(x)|] = \frac{f'(x)}{f(x)}

Explanation:

  • The Derivative of  lnf(x):\ \ln|f(x)| :
    • By the chain rule, the derivative of  lnf(x)\ \ln|f(x)| with respect to  x\ x is: ddx[lnf(x)]=1f(x)f(x)=f(x)f(x)\\ \frac{d}{dx}[\ln|f(x)|] = \frac{1}{f(x)} \cdot f'(x) = \frac{f'(x)}{f(x)}

    • This means that if you encounter  f(x)f(x)\ \frac{f'(x)}{f(x)} , it is the derivative of  lnf(x).\ \ln|f(x)| .

Integration of  f(x)f(x)\ \frac{f'(x)}{f(x)} :

If you need to integrate  f(x)f(x)\ \frac{f'(x)}{f(x)} with respect to  x\ x , the result will be:

f(x)f(x)dx=lnf(x)+C\\ \int \frac{f'(x)}{f(x)} \, dx = \ln|f(x)| + C

infoNote

Example:

Suppose  f(x)=x2+1\ f(x) = x^2 + 1 . Then:

f(x)=2x\\ f'(x) = 2x

f(x)f(x)=2xx2+1\\ \frac{f'(x)}{f(x)} = \frac{2x}{x^2 + 1}

The integral of  2xx2+1\ \frac{2x}{x^2 + 1} with respect to  x\ x is:

2xx2+1dx=lnx2+1+C\\ \int \frac{2x}{x^2 + 1} \, dx = \ln|x^2 + 1| + C

Summary:

infoNote
  • Expression:  f(x)f(x)\ \frac{f'(x)}{f(x)}
  • Integral:  f(x)f(x)dx=lnf(x)+C\ \int \frac{f'(x)}{f(x)} \, dx = \ln|f(x)| + C This is a common result in calculus and is particularly useful in solving problems involving logarithmic differentiation and integration.
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