See what we can offer to your school
"SimpleStudy just makes sense...”
Get the best plan for your school
15 cards from this deck
Energy to raise 1 kg of a material by 1°C
J/kg°C
Lowercase c
ΔE=m×c×ΔθΔE = m × c × ΔθΔE=m×c×Δθ
Change in thermal energy (J)
Mass of the object (kg)
Specific heat capacity (J/kg°C)
Change in temperature (°C or K)
Requires more energy to increase temperature
Needs less energy to increase temperature
P=V×IP = V × IP=V×I
E=P×tE = P × tE=P×t
c=ΔEm×Δθc = \frac{ΔE}{m × Δθ}c=m×ΔθΔE
High specific heat capacity absorbs lots of heat without large temperature rise
Low specific heat capacity
Select your subjects, and get access to A+ resources today.