Photo AI

Given the graph of the function f(x), calculate the values of the following: (a) f(2) (b) f'(2) (c) The area under the curve between x = 1 and x = 3. - Leaving Cert Home Economics - Question 6 - 2010

Question icon

Question 6

Given-the-graph-of-the-function-f(x),-calculate-the-values-of-the-following:---(a)-f(2)---(b)-f'(2)---(c)-The-area-under-the-curve-between-x-=-1-and-x-=-3.-Leaving Cert Home Economics-Question 6-2010.png

Given the graph of the function f(x), calculate the values of the following: (a) f(2) (b) f'(2) (c) The area under the curve between x = 1 and x = 3.

Worked Solution & Example Answer:Given the graph of the function f(x), calculate the values of the following: (a) f(2) (b) f'(2) (c) The area under the curve between x = 1 and x = 3. - Leaving Cert Home Economics - Question 6 - 2010

Step 1

(a) f(2)

96%

114 rated

Answer

To find f(2), locate x = 2 on the graph of the function. Read the corresponding y-value directly from the graph. Assume the graph shows that at x = 2, the y-value is 4. Therefore, f(2) = 4.

Step 2

(b) f'(2)

99%

104 rated

Answer

To find the derivative f'(2), determine the slope of the tangent line at the point where x = 2 on the graph. If the tangent line roughly rises 2 units for every 1 unit it moves horizontally, then the slope is 2. Hence, f'(2) = 2.

Step 3

(c) The area under the curve between x = 1 and x = 3.

96%

101 rated

Answer

To calculate the area under the curve from x = 1 to x = 3, use the definite integral method. If the graph indicates a simple shape (like a rectangle or trapezoid), apply the appropriate formula. For example, if the shape is a trapezoid with bases of lengths 3 and 5 and a height of 2, the area A can be calculated as:

A=12×(b1+b2)×h=12×(3+5)×2=16.A = \frac{1}{2} \times (b_1 + b_2) \times h = \frac{1}{2} \times (3 + 5) \times 2 = 16.

Thus, the area under the curve between x = 1 and x = 3 is 8.

Join the Leaving Cert students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;