Photo AI

Last Updated Sep 27, 2025

Permutations/Arrangements Simplified Revision Notes

Revision notes with simplified explanations to understand Permutations/Arrangements quickly and effectively.

user avatar
user avatar
user avatar
user avatar
user avatar

222+ students studying

Permutations/Arrangements

Overview

A permutation is an arrangement of objects in a specific order. Permutations are used to count the number of possible arrangements when the order of selection matters.

Key Concepts

Factorial (n!n!):

The factorial of nn is the product of all positive integers up to nn:

n!=n×(n1)×(n2)××1n! = n \times (n-1) \times (n-2) \times \ldots \times 1

Permutations of nn Distinct Objects:

The total number of arrangements of nn objects is given by:

n!n!

Permutations of rr Objects from nn Distinct Objects:

The number of ways to arrange rr objects from a set of nn distinct objects is:

P(n,r)=n!(nr)!P(n, r) = \frac{n!}{(n-r)!}

Permutations with Repetition:

If some objects are identical, the total permutations are reduced:

Permutations=n!p1!×p2!××pk!\text{Permutations} = \frac{n!}{p_1! \times p_2! \times \ldots \times p_k!}

Where p1,p2,,pkp_1, p_2, \ldots, p_k are the counts of identical items.


Worked Examples

infoNote

Example 1: Permutations of Distinct Objects

Problem: How many ways can the letters A, B, C, D be arranged?


Solution:

Step 1: Total number of letters (n)=4(n) = 4


Step 2: Calculate permutations:

4!=4×3×2×1=244! = 4 \times 3 \times 2 \times 1 = 24

Answer: There are 24 arrangements.


infoNote

Example 2: Selecting and Arranging rr Objects

Problem: In how many ways can 3 students be arranged in a line from a group of 5?


Solution:

Step 1: Total students (n)=5(n) = 5; Selected students (r)=3(r) = 3.


Step 2: Use the formula:

P(5,3)=5!(53)!=5×4×3×2×12×1=60P(5, 3) = \frac{5!}{(5-3)!} = \frac{5 \times 4 \times 3 \times 2 \times 1}{2 \times 1} = 60

Answer: There are 60 arrangements.


infoNote

Example 3: Permutations with Repetition

Problem: How many unique arrangements can be made from the letters in AABAAB?


Solution:

Step 1: Total letters (n)=3(n) = 3.


Step 2: Repeated letters: AA appears 2 times**.**


Step 3: Use the formula:

Permutations=n!p1!=3!2!=62=3\text{Permutations} = \frac{n!}{p_1!} = \frac{3!}{2!} = \frac{6}{2} = 3

Answer: There are 3 unique arrangements: AAB,ABA,BAAAAB, ABA, BAA.


Summary

  • Permutations calculate the number of arrangements when order matters.
  • Formulas:
    • n!n!: Arrangements of n distinct objects.
    • P(n,r)=n!(nr)!P(n, r) = \frac{n!}{(n-r)!}: Arrangements of r objects from n distinct objects.
    • With repetition:
n!p1!×p2!×\frac{n!}{p_1! \times p_2! \times \ldots}
  • Permutations are essential in counting problems and probability.
Books

Only available for registered users.

Sign up now to view the full note, or log in if you already have an account!

500K+ Students Use These Powerful Tools to Master Permutations/Arrangements

Enhance your understanding with flashcards, quizzes, and exams—designed to help you grasp key concepts, reinforce learning, and master any topic with confidence!

50 flashcards

Flashcards on Permutations/Arrangements

Revise key concepts with interactive flashcards.

Try Mathematics Flashcards

4 quizzes

Quizzes on Permutations/Arrangements

Test your knowledge with fun and engaging quizzes.

Try Mathematics Quizzes

29 questions

Exam questions on Permutations/Arrangements

Boost your confidence with real exam questions.

Try Mathematics Questions

27 exams created

Exam Builder on Permutations/Arrangements

Create custom exams across topics for better practice!

Try Mathematics exam builder

322 papers

Past Papers on Permutations/Arrangements

Practice past papers to reinforce exam experience.

Try Mathematics Past Papers

Other Revision Notes related to Permutations/Arrangements you should explore

Discover More Revision Notes Related to Permutations/Arrangements to Deepen Your Understanding and Improve Your Mastery

96%

114 rated

Permutations/Arrangements

Permutations/Arrangements

user avatar
user avatar
user avatar
user avatar
user avatar

380+ studying

200KViews
Load more notes

Join 500,000+ Leaving Cert students using SimpleStudy...

Join Thousands of Leaving Cert Students Using SimpleStudy to Learn Smarter, Stay Organized, and Boost Their Grades with Confidence!

97% of Students

Report Improved Results

98% of Students

Recommend to friends

500,000+

Students Supported

50 Million+

Questions answered