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Sine, Cosine, Tan Ratios Simplified Revision Notes

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Sine, Cosine, Tan Ratios

Understanding Sin, Cos, and Tan

The Crucial Point about Sin, Cos, and Tan

Right-Angled Triangles Only: Just like Pythagoras' Theorem, all the work involving Sin, Cos, and Tan only applies to right-angled triangles. This is crucial to remember because if the triangle isn't right-angled, these trigonometric ratios won't work directly. You might need to create a right-angled triangle by adding an auxiliary line.

Checking Your Calculator is in the Correct Mode

  • Calculator Mode: Before you begin solving problems involving Sin, Cos, and Tan, ensure your calculator is set to the correct mode. If your calculator is in the wrong mode, it might give you incorrect answers even if you're following all the steps correctly.
  • How to Check:
    • Enter sin 30 into your calculator.
    • If your calculator shows 0.5, it's in the correct mode (degrees mode).
    • If not, you need to switch to degrees mode (DEG).
  • Switching Modes: On most calculators, you can change the mode by pressing the MODE button and selecting the degrees option (DEG). The exact process may vary slightly depending on your calculator model.

Labelling the Sides of a Right-Angled Triangle

Before you start working out which trigonometric ratio (Sin, Cos, or Tan) you need, it's essential to correctly label the sides of your right-angled triangle.

  • Steps to Label the Sides:

    1. Hypotenuse (HH): This is the longest side, always opposite the right angle.
    2. Opposite (OO): This is the side directly opposite the angle θθ (the angle you are given or need to find).
    3. Adjacent (AA): This is the remaining side, the one next to the angle θθ but not the hypotenuse. image
  • Remember: The angle θθ (theta) is often used to represent an unknown angle in mathematics, just as xx is commonly used for unknown lengths.


Two Ways of Solving Trigonometry Problems

When tackling trigonometry problems in GCSE Maths, you have two main methods to choose from. Both methods are equally valid, so it's up to you to decide which one you prefer.

Steps Before Solving:

  1. Label
  2. Tick
  3. Tick
  4. Decide

  1. Label your right-angled triangle.
  2. Tick the information you know (lengths of sides, sizes of angles).
  3. Tick the information you need to work out.
  4. Decide whether the question requires using Sin, Cos, or Tan.

Method A: Use the Formula and Re-arrange

This method is best for students who are comfortable and confident with re-arranging formulas.

  • Key Formulas:
sin(θ)=OppositeHypotenuse\sin(\theta) = \frac{\text{Opposite}}{\text{Hypotenuse}} \\ cos(θ)=AdjacentHypotenuse\cos(\theta) = \frac{\text{Adjacent}}{\text{Hypotenuse}} \\ tan(θ)=OppositeAdjacent\tan(\theta) = \frac{\text{Opposite}}{\text{Adjacent}}
  • Steps: 4. Substitute the two known values into the appropriate formula. 5. Re-arrange the equation to solve for the unknown value.

Method B: Use the Formula Triangles

This is a clever way of solving trigonometry problems without needing to re-arrange formulas. Instead, you rely on a visual aid—the formula triangle.

image
  • Formula Triangles:
    • For Sin:
Triangle: OHsin(θ)\text{Triangle: } \frac{O}{H \sin(\theta)}
  • Cover the side you are solving for and use the remaining part of the triangle.
infoNote

For example:

  • For Cos:
Triangle: AHcos(θ)\text{Triangle: } \frac{A}{H \cos(\theta)}
infoNote

Example:

  • For Tan:
Triangle: OAtan(θ)\text{Triangle: } \frac{O}{A \tan(\theta)}
infoNote

Example:

  • Memory Aid:
    • SOHCAHTOA:
    • SOH: Sin = Opposite / Hypotenuse
    • CAH: Cos = Adjacent / Hypotenuse
    • TOA: Tan = Opposite / Adjacent

infoNote

Example: Solving a Trigonometry Problem Using Tan

Let's work through an example step by step to see how we can use the tangent (Tan) function to solve a trigonometry problem involving a right-angled triangle.

Problem: Find the length of the opposite side in the right-angled triangle where the angle θθ is 50°50\degree and the adjacent side is 1212 cmcm.


Step-by-Step Solution:

  1. Label the sides:
  • Hypotenuse (HH): The longest side, opposite the right angle.

  • Opposite (OO): The side opposite the angle you are working with.

  • Adjacent (AA): The side next to the angle, but not the hypotenuse. In this triangle:

  • The side we need to find is the Opposite (OO).

  • We know the Adjacent side (AA) is 1212 cmcm.

  • The angle θ is 50°50\degree.


  1. Identify what you are given:
  • We are given the angle θθ and the length of the adjacent side.

  1. Identify what you need to find:
  • We need to find the length of the opposite side (OO).

  1. Choose the correct trigonometric ratio:
  • Since we know the adjacent side and need to find the opposite side, we use the Tan function because:
tan(θ)=Opposite(O)Adjacent(A)\tan(\theta) = \frac{\text{Opposite(O)}}{\text{Adjacent(A)}}
  1. Set up the equation:
  • Use the formula:
tan(θ)=OA\tan(\theta) = \frac{\text{O}}{\text{A}}

Substituting the known values:

tan(50)=O12cm\tan(50^\circ) = \frac{O}{12 \, \text{cm}}
  1. Solve for the unknown:
  • Rearrange the equation to solve for OO:
O=tan(50)×12cmO = \tan(50^\circ) \times 12 \, \text{cm}
  • Use your calculator to find tan(50°)1.1918tan(50\degree)≈1.1918.
  • Multiply:
O=1.1918×12cm14.3cmO=1.1918×12 cm≈14.3 cm
  1. Final answer:
  • The length of the opposite side is approximately 14.3 cm14.3\ cm (to 11 decimal place).

infoNote

Example: Solving a Trigonometry Problem Using Cosine (Cos)

Let's go through a problem that requires the use of the cosine (Cos) function to find the length of the hypotenuse in a right-angled triangle.

Problem: Find the length of the hypotenuse in a right-angled triangle where the angle θθ is 26°26\degree and the adjacent side is 3.13.1m.


Step-by-Step Solution:

  1. Label the sides:
  • Hypotenuse (HH): The longest side, opposite the right angle.

  • Opposite (OO): The side opposite the angle θθ.

  • Adjacent (A): The side next to the angle θθ, but not the hypotenuse. In this triangle:

  • The side we need to find is the Hypotenuse (HH).

  • We know the Adjacent side (AA) is 3.1$$m.

  • The angle θθ is 26°26\degree.


  1. Identify what you are given:
  • We are given the angle θθ and the length of the adjacent side.

  1. Identify what you need to find:
  • We need to find the length of the hypotenuse (HH).

  1. Choose the correct trigonometric ratio:
  • Since we know the adjacent side and need to find the hypotenuse, we use the Cosine (Cos) function because:
cos(θ)=Adjacent(A)Hypotenuse(H)\cos(\theta) = \frac{\text{Adjacent} \, (A)}{\text{Hypotenuse} \, (H)}
  1. Set up the equation:
  • Use the formula:
cos(θ)=AH\cos(\theta) = \frac{A}{H}

Substituting the known values:

cos(26)=3.1mH\cos(26^\circ) = \frac{3.1 \, \text{m}}{H}
  1. Solve for the unknown:
  • Rearrange the equation to solve for HH:
H=Acos(θ)=3.1mcos(26)H = \frac{A}{\cos(\theta)} = \frac{3.1 \, \text{m}}{\cos(26^\circ)}
  • Use your calculator to find cos$$(26\degree)≈0.8988.
  • Calculate:
H=3.1 m0.89883.45 mH=\frac{3.1 \ m}{0.8988}≈3.45\ m
  1. Final answer:
  • The length of the hypotenuse is approximately 3.45 m3.45 \ m (to 22 decimal places).

infoNote

Example: Finding the Angle Using Sine (Sin)

In this example, we will use the Sine function to determine the angle θθ in a right-angled triangle.

Problem: Find the angle θθ in a right-angled triangle where the opposite side to the angle is 66mm, and the hypotenuse is 88mm.


Step-by-Step Solution:

  1. Label the sides:
  • Hypotenuse (HH): The longest side, opposite the right angle.

  • Opposite (OO): The side directly opposite the angle θθ.

  • Adjacent (AA): The side next to the angle θθ, but not the hypotenuse. In this triangle:

  • The Hypotenuse (HH) is 8 mm8 \ mm.

  • The Opposite side (OO) is 6 mm6 \ mm.

  • We need to find the angle θθ.


  1. Identify what you are given:
  • We are given the lengths of the opposite side and the hypotenuse.

  1. Identify what you need to find:
  • We need to find the angle θθ.

  1. Choose the correct trigonometric ratio:
  • Since we know the opposite side and the hypotenuse, we use the Sine (Sin) function because:
sin(θ)=Opposite(O)Hypotenuse(H)\sin(\theta) = \frac{\text{Opposite} \, (O)}{\text{Hypotenuse} \, (H)}
  1. Set up the equation:
  • Use the formula:
sin(θ)=OH\sin(\theta) = \frac{O}{H}

Substituting the known values:

sin(θ)=6mm8mm\sin(\theta) = \frac{6 \, \text{mm}}{8 \, \text{mm}}
  1. Calculate the sine of the angle:
  • Calculate:
sin(θ)=0.75\sin(\theta) = 0.75
  1. Find the angle θθ:
  • To find θθ, you need to use the inverse sine function sin1sin^{−1}:
θ=sin1(0.75)\theta = \sin^{-1}(0.75)
  • Using a calculator:
θ47.79°θ≈47.79\degree
  1. Final answer:
  • The angle θθ is approximately 47.79°47.79° (to 22 decimal places).

infoNote

Example: Finding the Length of the Base in an Isosceles Triangle

In this example, we will use the Tangent (Tan) function to determine the length of the base of an isosceles triangle.

Problem: Find the base of the isosceles triangle with two equal sides of 1010cm and the angle between them being 40°40°.


Step-by-Step Solution:

  1. Label the sides:
  • Hypotenuse (HH): The longest side, opposite the right angle.

  • Opposite (OO): The side directly opposite the angle we are dealing with.

  • Adjacent (AA): The side next to the angle but not the hypotenuse. For this problem:

  • The Hypotenuse (HH) is 1010 cmcm (one of the equal sides).

  • The Opposite side (OO) is the height of the triangle (we will find this as an intermediate step).

  • The Adjacent side (AA) is half of the base (we will find this).


  1. Identify what you are given:
  • The Hypotenuse (HH) is 1010 cmcm.
  • The angle is 40°40°.

  1. Identify what you need to find:
  • The length of the base, which is twice the length of the adjacent side (AA) of the right-angled triangle we can create.

  1. Use trigonometry to solve:
  • Since we have the angle and the opposite side, and we need to find the adjacent side, we use the Tangent (Tan) function:
tan(θ)=OA\tan(\theta) = \frac{O}{A}

Rearranging the formula to solve for AA:

A=Otan(θ)A = \frac{O}{\tan(\theta)}

Substituting the values:

A=10cmtan(40)A = \frac{10 \, \text{cm}}{\tan(40^\circ)}
  1. Calculate:
  • Using a calculator:
A=10cm0.839111.91cmA = \frac{10 \, \text{cm}}{0.8391} \approx 11.91 \, \text{cm}
  1. Double the Adjacent to get the full base:
  • Since we only calculated half the base (AA), double it to find the full length:
Base=2×3.64cm=7.28cmBase=2×3.64 cm=7.28 cm
  1. Final answer:
  • The full length of the base of the isosceles triangle is approximately 7.28 cm7.28 \ cm.

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