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Solving Area/Volume Problems Simplified Revision Notes

Revision notes with simplified explanations to understand Solving Area/Volume Problems quickly and effectively.

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Solving Area/Volume Problems

Understanding the Problem

When solving area and volume problems, it's crucial to:

  1. Understand the Shape: Identify whether it's 2D (e.g., triangle, circle) or 3D (e.g., cylinder, sphere).
  2. Recall the Formulae: Ensure you use the correct formula for the area or volume of the shape.

Strategy for Solving Problems

  1. Identify the Given Values: Write down all measurements provided (e.g., radius, height, base).
  2. Substitute into the Formula: Insert the given values into the appropriate formula.
  3. Calculate and Simplify: Perform arithmetic operations carefully to find the answer.
  4. Verify Units: Ensure the result has the correct units (e.g., square units for area, cubic units for volume).

Worked Examples

infoNote

Example 1: Area of a Trapezium

Problem: Find the area of a trapezium with bases 10cm10 \, \text{cm} and 14cm14 \, \text{cm}, and height 8cm8 \, \text{cm}


Solution:

Step 1: Use the formula for the area of a trapezium:

Area=12×(Base1+Base2)×Height\text{Area} = \frac{1}{2} \times (\text{Base}_1 + \text{Base}_2) \times \text{Height}

Step 2: Substitute:

Area=12×(10+14)×8=12×24×8=96cm2\text{Area} = \frac{1}{2} \times (10 + 14) \times 8 = \frac{1}{2} \times 24 \times 8 = 96 \, \text{cm}^2

Answer: 96cm296 \, \text{cm}^2


infoNote

Example 2: Volume of a Cylinder

Problem: Calculate the volume of a cylinder with radius 5cm5 \, \text{cm} and height 10cm10 \, \text{cm}


Solution:

Step 1: Use the formula for the volume of a cylinder:

Volume=πr2h\text{Volume} = \pi r^2 h

Step 2: Substitute r=5r = 5 and h=10h = 10:

Volume=π(5)2(10)=250πcm3785.40cm3\text{Volume} = \pi (5)^2 (10) = 250\pi \, \text{cm}^3 \approx 785.40 \, \text{cm}^3

Answer: 785.40cm3785.40 \, \text{cm}^3


infoNote

Example 3: Combining Shapes

Problem: Find the surface area of a hemisphere with radius 7cm7 \, \text{cm}


Solution:

Step 1: Surface area formula of a hemisphere:

Surface Area=2πr2\text{Surface Area} = 2\pi r^2

Step 2: Substitute r=7r = 7:

Surface Area=2π(7)2=2π(49)=98πcm2307.88cm2\text{Surface Area} = 2\pi (7)^2 = 2\pi (49) = 98\pi \, \text{cm}^2 \approx 307.88 \, \text{cm}^2

Answer: 307.88cm2307.88 \, \text{cm}^2


Summary

  • Area Formulae:
    • Triangle: 12×Base×Height\frac{1}{2} \times \text{Base} \times \text{Height}
    • Trapezium: 12×(Base1+Base2)×Height\frac{1}{2} \times (\text{Base}_1 + \text{Base}_2) \times \text{Height}
  • Volume Formulae:
    • Cylinder: πr2h\pi r^2 h
    • Sphere: 43πr3\frac{4}{3} \pi r^3
  • Steps: Identify the shape, recall the formula, substitute values, and calculate.

Practice a variety of problems to become confident in applying these steps to solve complex area and volume problems.

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