Practice Problems (Junior Cert Mathematics): Revision Notes
Practice Problems
Problem:
The students in a Transition Year mini-company make and sell candles. They buy a solid rectangular block of wax measuring 35 cm by 45 cm by 16 cm.

(a) Work out the volume of the block of wax.
(b) The students are going to use this wax to make candles in the shape of cylinders. Each candle will have a radius of r cm and a height of 9 cm. Work out the volume of each candle, in terms of r and π.

(c) The students make 100 candles from the block of wax. In making the candles, 10% of the wax in the block is wasted. Use this information to work out the value of r, the radius of each candle. Give your answer correct to 1 decimal place.
(Junior Cycle Exam 2023)
Solutions:
The students in a Transition Year mini-company make and sell candles. They buy a solid rectangular block of wax measuring 35 cm by 45 cm by 16 cm.

(a) Work out the volume of the block of wax.
To find the volume of the rectangular block of wax, we use the formula for the volume of a rectangular prism:
- Step 1: Identify the dimensions of the block:
- Length = 35 cm (This is how long the block is.)
- Width = 45 cm (This is how wide the block is.)
- Height = 16 cm (This is how tall the block is.) Explanation: These are the three dimensions needed to calculate the volume. They tell us how much space the block takes up.
- Step 2: Plug in the values into the formula and calculate the volume:
- Volume = 35 × 45 × 16 = 25,200 cubic centimetres Explanation: We multiply the length, width, and height together in one step to find the total volume of the block.
Final Answer:
The volume of the block of wax is 25,200 cm³.
(b) The students are going to use this wax to make candles in the shape of cylinders. Each candle will have a radius of r cm and a height of 9 cm. Work out the volume of each candle, in terms of r and π.

Next, we need to find the volume of each cylindrical candle. We use the formula for the volume of a cylinder:
- Step 1: Identify the dimensions of the candle:
- Radius = r cm (This is half the diameter of the base of the cylinder.)
- Height = 9 cm (This is how tall the candle is.) Explanation: The radius and height are the key dimensions we need to calculate the volume of the cylinder.
- Step 2: Plug in the height and leave the radius as r since the problem asks for the answer in terms of r and π:
- Volume = π r² × 9 = 9π r² Explanation: We substitute the height (9 cm) into the formula, and leave r and π as they are because the question asks for the answer in these terms.
Final Answer:
The volume of each candle is 9π r² cm³.
(c) The students make 100 candles from the block of wax. In making the candles, 10% of the wax in the block is wasted. Use this information to work out the value of r, the radius of each candle. Give your answer correct to 1 decimal place.
Finally, we need to calculate the radius r of each candle, given that the students make 100 candles from the block of wax and 10% of the wax is wasted.
- Step 1: Calculate the total usable volume of wax after waste:
- Total Volume = 25,200 cm³ (This is the volume of the block of wax from part (a).)
- Wasted Wax = 0.1 × 25,200 = 2,520 cm³
- Usable Wax = 25,200 - 2,520 = 22,680 cm³ Explanation: First, we calculate how much wax is wasted (10% of the total volume). Then, we subtract the wasted wax from the total volume to find out how much wax is actually available for making candles.
- Step 2: Determine the total volume of 100 candles:
- Volume of 100 candles = Usable Wax = 22,680 cm³ Explanation: The total volume of all the candles combined must equal the total usable wax after waste.
- Step 3: Use the volume formula from part (b) to set up the equation:
- 100 × 9π r² = 22,680 Explanation: Since each candle has a volume of 9π r², the volume of 100 candles is 100 × 9π r². This must equal the total usable wax volume (22,680 cm³).
- Step 4: Simplify the equation to solve for r²:
- 900π r² = 22,680
- r² = 22,680/(900π) Explanation: We divide both sides of the equation by 900π to isolate r².
- Step 5: Calculate r and correct to 1 decimal place:
- r² = 22,680/(900π) ≈ 22,680/2827.43 ≈ 8.02
- r ≈ √8.02 ≈ 2.8 cm Explanation: We calculate r² by dividing 22,680 by 900π. Then, we take the square root to find r. The final answer is rounded to 1 decimal place as required.
Final Answer:
The radius r of each candle is 2.8 cm.
Exam Tip: In some Junior Cycle Exam questions, you may need to use answers from the first part of the question to answer a later part of a question. Be ready for these multipart problems in the exam.