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13 questions from this quiz
Inversely proportional
1662
Absolute temperature in Kelvin
273
P1V1T1=P2V2T2\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}T1P1V1=T2P2V2
0°C or 273 K
100,000 Pa
Simple whole-number ratios
1808
22.4 L
Contain equal numbers of molecules
8.31 J K⁻¹ mol⁻¹
PV=nRTPV = nRTPV=nRT
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