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12 questions from this quiz
Vertex above centre of circular base
Vertical distance vertex to base centre
Distance vertex to base edge point
l2=h2+r2l^2 = h^2 + r^2l2=h2+r2
V=13πr2hV = \frac{1}{3}\pi r^2 hV=31πr2h
πrl\pi r lπrl
πrl+πr2\pi r l + \pi r^2πrl+πr2
Perpendicular height hhh
Slant height lll
10 cm
13 cm
Use Pythagoras to find hhh
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