Area of Triangles and Parallelograms (Leaving Cert Mathematics): Quizzes

$\frac{1}{2} \times \text{base} \times \text{height}$

Any side of the triangle

Distance from base to opposite vertex at 90°

It stays the same

$48$ cm²

$12$ cm

Creates two congruent triangles

Bisects it (cuts it in half)

$\text{base} \times \text{height}$

$90$ cm²

Shortest distance between parallel sides

Square units like cm² or m²