Bernoulli Trials (Leaving Cert Mathematics): Quizzes

Exactly two

$q = 1 - p$

Probability of success remains constant

It does not affect another

$\binom{n}{k} p^k q^{n-k}$

$\frac{n!}{k!(n-k)!}$

$q^{n-1} \times p$

$\binom{n-1}{k-1} p^k q^{n-k}$

$0.3456$

$0.063$

Total number of trials

Binomial distribution