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12 questions from this quiz
Exactly two
q=1−pq = 1 - pq=1−p
Probability of success remains constant
It does not affect another
(nk)pkqn−k\binom{n}{k} p^k q^{n-k}(kn)pkqn−k
n!k!(n−k)!\frac{n!}{k!(n-k)!}k!(n−k)!n!
qn−1×pq^{n-1} \times pqn−1×p
(n−1k−1)pkqn−k\binom{n-1}{k-1} p^k q^{n-k}(k−1n−1)pkqn−k
0.34560.34560.3456
0.0630.0630.063
Total number of trials
Binomial distribution
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