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12 questions from this quiz
sinAcosB+cosAsinB\sin A \cos B + \cos A \sin BsinAcosB+cosAsinB
cosAcosB+sinAsinB\cos A \cos B + \sin A \sin BcosAcosB+sinAsinB
tanA+tanB1−tanAtanB\frac{\tan A + \tan B}{1 - \tan A \tan B}1−tanAtanBtanA+tanB
The minus becomes a plus
6+24\frac{\sqrt{6} + \sqrt{2}}{4}46+2
sin30°\sin 30°sin30°
By dividing sine formula by cosine formula
No, they do not apply
cosθ\cos \thetacosθ
Finding derivatives of functions
sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1sin2θ+cos2θ=1
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