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12 questions from this quiz
sin(2θ)=2sin(θ)cos(θ)\sin(2\theta) = 2\sin(\theta)\cos(\theta)sin(2θ)=2sin(θ)cos(θ)
cos(2θ)=cos2(θ)−sin2(θ)\cos(2\theta) = \cos^2(\theta) - \sin^2(\theta)cos(2θ)=cos2(θ)−sin2(θ)
cos(2θ)=1−2sin2(θ)\cos(2\theta) = 1 - 2\sin^2(\theta)cos(2θ)=1−2sin2(θ)
tan(2θ)=2tan(θ)1−tan2(θ)\tan(2\theta) = \frac{2\tan(\theta)}{1 - \tan^2(\theta)}tan(2θ)=1−tan2(θ)2tan(θ)
Three
2425\frac{24}{25}2524
−119169\frac{-119}{169}169−119
θ=22.5°\theta = 22.5°θ=22.5° and θ=112.5°\theta = 112.5°θ=112.5°
sin2(θ)+cos2(θ)=1\sin^2(\theta) + \cos^2(\theta) = 1sin2(θ)+cos2(θ)=1
Sine sum identity
Physics
Dividing loses solutions where cosx=0\cos x = 0cosx=0
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