Solving Right-Angled Triangles (Leaving Cert Mathematics): Quizzes

Using trig ratios to find unknown sides/angles

Two pieces (one side & one angle, or 2 sides)

$\sin \theta = \frac{\text{opposite}}{\text{hypotenuse}}$

$\cos \theta = \frac{\text{adjacent}}{\text{hypotenuse}}$

$\tan \theta = \frac{\text{opposite}}{\text{adjacent}}$

Tangent = Opposite ÷ Adjacent

The longest side, opposite the right angle

$\tan^{-1}$

When you know two sides and want to find angle

Degree mode

4 decimal places

$x = \frac{8}{\cos 32°}$