Remainder Theorem (Grade 12 NSC Matric Mathematics): Flashcards

📚Flashcards
Remainder Theorem
Sign up to keep revising.Create a free account to study more flashcards and track your progress.

Practise the cards

10 cards from this deck

Show

Remainder theorem formula for p(x)÷(cx−d)p(x) \div (cx - d)

R=p(dc)R = p(\frac{d}{c})

To solve cx−d=0cx - d = 0 for xx

x=dcx = \frac{d}{c}

Q(x)Q(x) in p(x)=(cx−d)×Q(x)+Rp(x) = (cx - d) \times Q(x) + R

The quotient (result of division)

RR in p(x)=(cx−d)×Q(x)+Rp(x) = (cx - d) \times Q(x) + R

The remainder (a constant value)

Nature of remainder in remainder theorem

Always a constant, never a polynomial

When remainder R=0R = 0 for divisor (cx−d)(cx - d)

(cx−d)(cx - d) is a factor of p(x)p(x)

Step 1: Applying remainder theorem

Identify the linear divisor in form (cx−d)(cx - d)

Finding substitution value from (cx−d)(cx - d)

Solve cx−d=0cx - d = 0 to get x=dcx = \frac{d}{c}

Remainder theorem vs long division

Saves time in calculations

Caution when using remainder theorem

Be careful with negative signs when substituting

Explore Grade 12 NSC Matric Mathematics Revision Notes by Topics

Explore Grade 12 NSC Matric Mathematics Model Answers by Topics

Explore Grade 12 NSC Matric Mathematics Exam Questions by Topics

Join 100,000+ NSC Matric students studying Flashcards with us.

Select your subjects, and get access to A+ resources today.