Application of FCP to Probability Problems (Grade 12 NSC Matric Mathematics): Flashcards

When sample space is very large

$P(E) = \frac{n(E)}{n(S)}$

Total number of arrangements of event E

Total number of arrangements of sample space S

$P(B) = 1 - P(\text{not B})$

Same number of choices available each time

Number of choices decreases each time

$10^4 = 10,000$

$10 \times 9 \times 8 \times 7 = 5,040$

Use complement: calculate 'none' and subtract from 1