Revision (Grade 12 NSC Matric Mathematics): Flashcards

$\bar{x} = \frac{\sum x_i}{n}$

Middle value when data is ordered

Maximum value - Minimum value

$Q_3 - Q_1$

$\sigma = \sqrt{\frac{\sum (x_i - \bar{x})^2}{n}}$

Min, $Q_1$, Median ($Q_2$), $Q_3$, Max

68%

95%

Mean > Median

Mean < Median