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10 questions from this quiz
12×base×height\frac{1}{2} \times \text{base} \times \text{height}21×base×height
Their bases
Area
Parallel lines
In the same proportion
ADDB=AEEC\frac{AD}{DB} = \frac{AE}{EC}DBAD=ECAE
Half the length of the third side
Bisects it
2:32:32:3
12\frac{1}{2}21
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