Application of FCP to Counting Problems (Grade 12 NSC Matric Mathematics): Quizzes

$8 \times 7 \times 6 = 336$

$\frac{n!}{n_1! \times n_2!}$

$3$

$6! \times 2! = 1440$

Total arrangements minus forbidden ones

$\frac{7!}{2! \times 2!} = 1260$

$\frac{6!}{2!} = 360$

$6 \times 5 \times 4 = 120$

When they must remain adjacent

$\frac{5!}{2!} + \frac{5!}{2!} = 120$