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10 questions from this quiz
Makes it less than the emf
When no current flows (I=0I = 0I=0)
Voltage drop across internal resistance
P=I2rP = I^2rP=I2r
As a resistor in series with emf source
0.20.20.2 V
23.223.223.2 V
3.03.03.0 Ω
It decreases
Rx=R2×R3R1R_x = \frac{R_2 \times R_3}{R_1}Rx=R1R2×R3
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