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10 questions from this quiz
Rate at which work is done
P=WtP = \frac{W}{t}P=tW
P=F×vP = F \times vP=F×v
One joule per second
750 watts
When force and velocity oppose each other
0 W
Maximum rate at which it can do work
10 W
W=12mv2+mghW = \frac{1}{2}mv^2 + mghW=21mv2+mgh
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