Dilution (HSC SSCE Chemistry): Revision Notes
Dilution
What is dilution?
In chemistry, we often need to reduce the concentration of a solution. This process is called dilution. It involves taking a measured volume of a more concentrated solution (the original solution) and adding water to increase the total volume, which decreases the concentration.
The key principle to understand is that when we dilute a solution, we are only adding water - we are not adding or removing any solute. This means the total amount of solute particles remains constant throughout the dilution process.
Understanding the dilution principle
When you dilute a solution, imagine you have a certain number of solute particles dissolved in a small volume of water. When you add more water, those same particles are now spread out in a larger volume. The particles haven't disappeared - they're just more spread out, making the solution less concentrated.
For example, if you have of a solution and dilute it to by adding water, the same number of solute particles that were in are now in . The particles are simply more dispersed throughout the larger volume.
The dilution equation
Since the amount of solute stays the same before and after dilution, we can write:
Amount of solute in original solution = Amount of solute in diluted solution
We know that:
- Amount of solute = concentration × volume
Therefore:
- Amount in original solution = original concentration × original volume
- Amount in diluted solution = final concentration × final volume
Since these amounts are equal:
Where:
- = original (initial) concentration
- = original (initial) volume
- = final (diluted) concentration
- = final (total) volume
This is the dilution equation:
Using the dilution equation
The dilution equation is very flexible. You can use any units for concentration (, , , ) and any units for volume ( or ), as long as you use the same units on both sides of the equation.
Rearranging the dilution equation to find different unknowns:
-
To find the final concentration:
-
To find the final volume:
-
To find the initial concentration:
-
To find the initial volume:
The dilution factor approach
There's a simple intuitive way to think about dilution problems. If you want to dilute a solution by a factor of , you need to increase the volume by a factor of .
For example:
- To dilute by a factor of , increase to (or to )
- To dilute by a factor of , increase to
Worked examples
Let's look at how to apply the dilution equation to solve practical problems.
Worked Example 1: Finding the concentration of a diluted sucrose solution
A sample of aqueous sucrose solution with concentration is diluted to using a pipette and volumetric flask. What is the concentration of the diluted solution?
Solution:
We need to find , so we rearrange the dilution equation:
Substituting values:
Answer: The concentration of the diluted solution is 4.21 g mL⁻¹
Important: Ensure that volumes use the same units throughout (millilitres in this case).
Worked Example 2: Finding the final volume needed for dilution
What volume should of a solution of potassium nitrate be diluted to in order to make a solution?
Solution:
We need to find , so we rearrange the dilution equation:
Substituting values:
Answer: The solution should be diluted to 250 mL
Important: Ensure that concentrations use the same units (mol L⁻¹ in this case).
Practical application: Making dilutions in the laboratory
When making dilutions in the laboratory, we use precision glassware such as pipettes and volumetric flasks to ensure accurate measurements.
The dilution process typically involves:
- Using a pipette to measure a precise volume of the original solution
- Transferring this to a volumetric flask
- Adding water and mixing thoroughly
- Making up to the mark on the volumetric flask with water
Investigation 8.2: Making and diluting solutions using volumetric glassware
This investigation demonstrates how to prepare solutions of known concentration and use serial dilutions to create a range of concentrations. Colorimetry is used to measure differences in colour intensity between solutions, which relates to their concentrations.
Aim: To make an original solution of known concentration, dilute it to make other solutions of known concentration, then use these to determine the unknown concentration of a solution.
Materials:
- Approximately of potassium permanganate,
- solution of unknown concentration
- Appropriate volumetric glassware (volumetric flasks, pipettes)
Safety considerations:
Before starting any practical work, complete a risk assessment to identify potential hazards and how to manage them safely. Potassium permanganate is an oxidising agent and can stain skin and clothing.
Method:
- Accurately weigh approximately of
- Use this mass and a volumetric flask to accurately prepare solution A
- Calculate the concentration of solution A
- Use volumetric glassware to dilute solution A by a factor of to make solution B
- Dilute solution B by a factor of to make solution C
- Dilute solution C by a factor of to make solution D
- Dilute solution D by a factor of to make solution E
- Compare the colours of solutions A–E qualitatively, or use a colorimeter to measure light intensity passing through each solution quantitatively
- Compare the colour intensity of the unknown solution with your known solutions to determine its concentration
Results:
Record your results in a table similar to this:
| Solution | Concentration of solution (mol L⁻¹) | Qualitative comparison of colour or intensity of light passing through solutions |
|---|---|---|
| A | ||
| B | ||
| C | ||
| D | ||
| E | ||
| Unknown |
Analysis:
You can analyse your results by:
- Taking photographs to show qualitative differences in colour between solutions
- Plotting a graph of colour intensity versus if using a colorimeter
The trend you should observe is that as concentration increases, the colour intensity increases (or less light passes through the solution).
Conclusion:
By comparing the colour intensity of the unknown solution with your standard solutions, you can determine its concentration. The accuracy of your answer will depend on your measurement method.
Key Concepts to Remember:
- Molarity is the number of moles of solute per litre of solution
- Standard solutions are solutions where the concentration is accurately known
- When solutions are diluted, the total amount of solute remains constant - only water is added
- The same number of solute particles are present in both the original and diluted solutions
Exam Tips:
- Always check that you're using the same units on both sides of the dilution equation
- Remember that is the final total volume, not the volume of water added
- Write down which variable you're solving for before rearranging the equation
- Show all steps in your working, including the rearrangement of the formula
Remember!
- The dilution equation is - this relates the original and final concentrations and volumes
- The amount of solute stays constant during dilution - you're only adding water, not adding or removing solute
- Use consistent units - ensure concentrations have the same units and volumes have the same units on both sides of the equation
- Dilution factor method - to dilute by a factor of , multiply the volume by (e.g., to dilute by , change to )
- Precision glassware matters - use pipettes and volumetric flasks for accurate dilutions in the laboratory