Titrations (AQA A-Level Chemistry): Flashcards

Moles of acid = moles of base; neutralisation complete

Solution of known concentration added in titration

Calculate moles of titrant using concentration × volume

$\text{moles} = \text{concentration} \times \text{volume}$

Write the balanced equation

$\text{HCl} + \text{NaOH} \to \text{NaCl} + \text{H}_2\text{O}$

0.020 dm³

1:1

$\text{concentration} = \frac{\text{moles}}{\text{volume}}$

0.025 dm³