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Moles of acid = moles of base; neutralisation complete
Solution of known concentration added in titration
Calculate moles of titrant using concentration × volume
moles=concentration×volume\text{moles} = \text{concentration} \times \text{volume}moles=concentration×volume
Write the balanced equation
HCl+NaOH→NaCl+H2O\text{HCl} + \text{NaOH} \to \text{NaCl} + \text{H}_2\text{O}HCl+NaOH→NaCl+H2O
0.020 dm³
1:1
concentration=molesvolume\text{concentration} = \frac{\text{moles}}{\text{volume}}concentration=volumemoles
0.025 dm³
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