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10 questions from this quiz
Derivative 2x2x2x is almost present as xxx
dx=du2xdx = \frac{du}{2x}dx=2xdu
13(1+x2)32+C\frac{1}{3}(1 + x^2)^{\frac{3}{2}} + C31(1+x2)23+C
u=1+cos(2x)u = 1 + \cos(2x)u=1+cos(2x)
−12ln∣1+cos(2x)∣+C-\frac{1}{2} \ln|1 + \cos(2x)| + C−21ln∣1+cos(2x)∣+C
x2x^2x2 in exponent; derivative 2x2x2x present
12ex2+C\frac{1}{2} e^{x^2} + C21ex2+C
u=ln(x)u = \ln(x)u=ln(x)
x=sec(θ)x = \sec(\theta)x=sec(θ)
x=tan(θ)x = \tan(\theta)x=tan(θ)
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