Power and efficiency of an engine (AQA A-Level Physics): Flashcards

$P_{ ext{input}} = ext{calorific value} imes ext{flow rate}$

Energy released per kilogram of fuel burned

Theoretical max power output assuming no frictional losses

$P_{ ext{out}} = Tomega$ (torque × angular velocity)

$P_{ ext{friction}} = P_{ ext{ind}} - P_{ ext{out}}$

746 W

$\omega = \frac{\text{rpm} \times 2\pi}{60}$

$\eta = \frac{P_{\text{out}}}{P_{\text{ind}}}$

$\varepsilon = \frac{P_{\text{ind}}}{P_{\text{input}}}$

$\frac{P_{\text{out}}}{P_{\text{input}}} = \eta \times \varepsilon$