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Energy to raise 1 kg by 1°C without state change
J kg−1^{-1}−1 °C−1^{-1}−1 or J kg−1^{-1}−1 K−1^{-1}−1
Q=mcΔθQ = mc\Delta\thetaQ=mcΔθ
4190
P=VIP = VIP=VI
c=VItmΔθc = \frac{VIt}{m\Delta\theta}c=mΔθVIt
Δθ=ghc\Delta\theta = \frac{gh}{c}Δθ=cgh
Independent of mass
Smaller temp change for same energy
Energy lost by hot object = energy gained by cold water
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