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10 cards from this deck
Force per unit charge on small positive test charge
E=FQE = \frac{F}{Q}E=QF
Newton per coulomb (NC−1\text{NC}^{-1}NC−1)
Volt per metre (Vm−1\text{Vm}^{-1}Vm−1)
Yes, 1 NC−1=1 Vm−11 \text{ NC}^{-1} = 1 \text{ Vm}^{-1}1 NC−1=1 Vm−1
E=Q4πε0r2E = \frac{Q}{4\pi\varepsilon_0 r^2}E=4πε0r2Q
Decreases with square of distance (∝1r2\propto \frac{1}{r^2}∝r21)
E=VdE = \frac{V}{d}E=dV
8.85×10−12 F m−18.85 \times 10^{-12} \text{ F m}^{-1}8.85×10−12 F m−1
Yes, direction is that of force on positive test charge
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