Electric field strength (2.0) (AQA A-Level Physics): Quizzes

$E = \frac{F}{Q}$

$\text{NC}^{-1}$ and $\text{Vm}^{-1}$

$E = \frac{Q}{4\pi\varepsilon_0 r^2}$

So its own field doesn't distort measured field

$E = \frac{V}{d}$

Decreases with square of distance

Direction of force on positive test charge

Field strength magnitude and direction

$8.85 \times 10^{-12} \text{ F m}^{-1}$

Vector quantity